Matematika mohon bantuannya yg nomer 3​

adolffaheyulv – June 08, 2023

mohon bantuannya yg nomer 3​

f(x) = (6x-3)^-4

f'(x) = -4(6x-3)^-5.(6)

f'(x) = -24(6x-3)^-5

f'(1) = -24(6.1-3)^-5

f'(1) = -24(3)^-5

f'(1) = -24/3^5

f'(1) = -24/243

f'(1) = -8/81

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